2(x^2+5x+6)=-x(x+2)

Solution for 2(x^2+5x+6)=-x(x+2) equation:

2(x^2+5x+6)=-x(x+2)

We move all terms to the left:

2(x^2+5x+6)-(-x(x+2))=0

We multiply parentheses

2x^2+10x-(-x(x+2))+12=0


We calculate terms in parentheses: -(-x(x+2)), so:

-x(x+2)

We multiply parentheses

-x^2-2x

We add all the numbers together, and all the variables

-1x^2-2x

Back to the equation:

-(-1x^2-2x)


We get rid of parentheses

2x^2+1x^2+2x+10x+12=0

We add all the numbers together, and all the variables

3x^2+12x+12=0

a = 3; b = 12; c = +12;
Δ = b2-4ac
Δ = 122-4·3·12
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{6}=-2$